B = 2010^2
= 2010 . 2010
A= 2009.2010
=> 2009 < 2010
Nên B < A
Ta có
A=2009x2010
B=20102=2010x2010
Vì 2010>2009
Nên A<B
Bai 1.Tim x, y biet :
2x(3y-2)+(3y-2) = -55
Bai 2 .a) So sanh : -22/45 va -51/103
b) So sanh A = 2009^2009 +1 / 2009^2010 va B = 2009^2010-2/2009^2011-2
Bai 3 :
a)Tim so tu nhien co 3 chu so , biet rang khi chia so do cho cac so 25, 28,35thi duoc cac so du lan luot la 5,8,15
b)Tim x: (x+1)+(x+2)+(x+3)+...+(x+100)=205550
2008/2009+2009/2010+2010+2011+2011/2008
va 4
so sanh
So sanh :2009^2009+1/2009^2010+1 va 2009^2010-2/2009^2011-2
so sanh
A=2008/2009+2009/2010+2010+2011
B=2008+2009+2010/2009+2010+2011
so sanh: A=2009^2009+1/2009^2010+1 và B=2009^2010-2/2009^2011-2
So sanh so A va B ma ko tinh gia tri cu the cua chung
a, A=2010×2010
B = 2009×2011
b, A=234234×233
B=233233×234
So sanh : U = \(\frac{2009^{2005}+1}{2009^{2010}+1}\)va V = \(\frac{2009^{2010}+2}{2009^{2011}+2}\)
so sanh A va B
A =\(\frac{2009}{2010}\) +\(\frac{2010}{2011}\) B =\(\frac{2009+2010}{2010+2011}\)
bài 3
a,tìm x,y biết : số 1996xy chia hết cho 2,5,9
b,so sánh
A= 2009/2010 + 2010/2011 + 2011/2012 + 2012/2009 va 4
