Question

So sánh: 

A = 10^2006 +1 phần 10^2007 + 1 và B = 10^2007 + 1 phần 10^2008 + 1

 

 

        

Answer 1

A=\(\frac{10^{2006}+1}{10^{2007}+1}\)

10.A=\(\frac{10.\left(10^{2006}+10\right)}{10^{2007}+1}\)

=\(1+\frac{9}{10^{2007}+1}\)

B=\(\frac{10^{2007}+1}{10^{2008}+1}\)

\(10.B=\frac{10.\left(10^{2007}+10\right)}{10^{2008}+1}\)

= \(1+\frac{9}{10^{2008}+1}\)

Vì\(1+\frac{9}{10^{2007}+1}>1+\frac{9}{10^{2008}+1}\) nên 10A > 10B \(\Rightarrow A>B\)

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