Ta có: \(\sqrt{5}< \sqrt{16}\left(=4\right)\)
\(\Rightarrow\sqrt{5}-4< 0\)
\(mà2\sqrt{3}>0\)
\(\Rightarrow2\sqrt{3}>\sqrt{5}-4\)
Ta có: \(\sqrt{5}< \sqrt{12}\)và \(-4< 0\)
\(\Rightarrow\sqrt{5}-4< \sqrt{12}+0=\sqrt{12}\)
mà \(\sqrt{12}=\sqrt{4.3}=\sqrt{4}.\sqrt{3}=2\sqrt{3}\)
\(\Rightarrow2\sqrt{3}=\sqrt{5}-4\)