a) ta có: -33/ 37 = -0,89
-34/35 = -0,97
=> -0,89 > -0,97 => -33/37> -34/35
b) ta có: \(\frac{n+1}{n+2}=\frac{n}{n+2}+\frac{1}{n+2}\)
mà \(\frac{n}{n+2}>\frac{n}{n+3}\Rightarrow\frac{n}{n+2}+\frac{1}{n+2}>\frac{n}{n+3}\)
\(\Rightarrow\frac{n+1}{n+2}>\frac{n}{n+3}\)
a) ta có: \(\frac{-33}{7}\) = -0,89
\(\frac{-34}{35}\)= -0,97
=> -0,89 > -0,97 => \(\frac{-33}{37}\)> \(\frac{-34}{35}\)
b) ta có: n+1n+2 =nn+2 +1n+2
mà nn+2 >nn+3 ⇒nn+2 +1n+2 >nn+3
⇒n+1n+2 >nn+3