Các câu hỏi tương tự
So sanh A va B, biet :
a)\(A=\frac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8};B=\frac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}\)
b)\(A=\frac{7^{10}}{1+7+7^2+...+7^9};B=\frac{5^{10}}{1+5+5^2+...+5^9}\)
so sanh \(y=\frac{10^{6+1}}{10^{5+1}}\)va \(y=\frac{10^{7+1}}{10^{6+1}}\)
so sanh \(y\frac{10^{6+1}}{10^{5+1}}\)va\(y\frac{10^{7+1}}{10^{6+1}}\)
So sanh: C= 10^7+4/10^7-1 va D=10^7+1/10^7+4
So sanh: C= 10^7+4/10^7-1 va D=10^7+1/10^7+4
so sanh cac phan so sau: 10^6+1/10^5+1 va 10^7+1/10^6+1
1so sanh \(y=\frac{10^6+1}{10^{5+1}}\)va \(y\frac{10^{7+1}}{10^{6+1}}\)2x
Hãy so sánh:
a) A= \(\frac{178}{179}+\frac{179}{180}+\frac{183}{181}\)với 3.
b) A= \(\frac{1+5+5^2+5^3+...+5^{10}+5^{11}}{1+5+5^2+5^3+...+5^9+5^{10}}\)và B=\(\frac{1+7+7^2+7^3+...+7^{10}+7^{11}}{1+7+7^2+7^3+...+7^9+7^{10}}\)
SO SANH:
\(A=\frac{10^9+1}{10^{10}+1}\)
\(B=\frac{10^7+1}{10^8+1}\)