\(A=10^5+\frac{4}{10^5}-1=\frac{10^{10}}{10^5}+\frac{4}{10^5}-\frac{10^5}{10^5}=\frac{10^{10}+4-10^5}{10^5}=\frac{9999900004}{10^5}=99999.00004\)
\(B=10^5+\frac{3}{10^5}-2=\frac{10^{10}}{10^5}+\frac{3}{10^5}-\frac{10^5.2}{10^5}=\frac{10^{10}+3-10^5.2}{10^5}=\frac{9999800003}{10^5}=99998.00003\)
\(C\text{ó}99999.00004>99998.00003\Rightarrow A>B\)
Hay \(\left(10^5+\frac{4}{10^5}-1\right)>\left(10^5+\frac{3}{10^5}-2\right)\)