\(\left(\frac{1}{32}\right)^2=\frac{1^7}{32^7}=\frac{1}{32^2}=\frac{1}{\left(2^5\right)^7}=\frac{1}{2^{35}}\)
\(\left(\frac{1}{16}\right)^9=\frac{1^9}{16^9}=\frac{1}{16^9}=\frac{1}{\left(2^4\right)^9}=\frac{1}{2^{36}}\)
Vì: 235 < 236 nên \(\frac{1}{2^{35}}>\frac{1}{2^{36}}\)
\(\Rightarrow\left(\frac{1}{32}\right)^7>\left(\frac{1}{16}\right)^9\)