Question

So sánh  (-1/16)¹⁰⁰ và (-1/2)⁵⁰⁰

                  (-32)⁹ và (-18)¹³

 

 

 

Answer 1

Toán 6 ? 

Ta có : 

\(\left(-\frac{1}{16}\right)^{100}=\left(\frac{1}{16}\right)^{100}=\frac{1}{16^{100}}\)

\(\left(-\frac{1}{2}\right)^{500}=\left(\frac{1}{2}\right)^{500}=\frac{1}{2^{500}}=\frac{1}{\left(2^4\right)^{125}}=\frac{1}{16^{125}}\)

Do \(\frac{1}{16^{100}}>\frac{1}{16^{125}}\left(16^{100}< 16^{125}\right)\)

\(\Rightarrow\left(-\frac{1}{16}\right)^{100}>\left(-\frac{1}{.2}\right)^{500}\)

Vậy ...

Answer 2

a) \(\left(-\frac{1}{2}\right)^{500}=\left[\left(-\frac{1}{2}^5\right)^{100}\right]=\left(\frac{-1}{32}\right)^{100}\)

Vì \(\left(-\frac{1}{16}\right)^{100}\) > \(\left(\frac{-1}{32}\right)^{100}\) nên \(\left(-\frac{1}{16}\right)^{100}>\left(-\frac{1}{2}\right)^{500}\)

b) Câu này mk ko bt

Bạn thông cảm

Answer 3

Câu a:

ta có: (-1/16)^100=(-1)^100/16^100=1/(2^4)^100=1/2^400     (1)

          (-1/2)^500=(-1)^500/2^500=1/2^500                              (2)

So sánh (1)và (2) ta thấy 2^400<2^500   => 1/2^400>1/2^500

=>(-1/16)^100>(-1/2)^500     (đpcm)

Answer 4

\(\left(-\frac{1}{16}\right)^{100}=\left(\frac{1}{16}\right)^{100}=\frac{1}{16^{100}}\)

\(\left(-\frac{1}{2}\right)^{500}=\left(\frac{1}{2}\right)^{500}\frac{1}{2^{500}}=\frac{1}{\left(2^4\right)^{125}}=\frac{1}{16^{125}}\)

Vì : \(\left(-\frac{1}{16^{100}}\right)>\frac{1}{16^{125}}\left(16^{100}< 16^{125}\right)\)

\(\Rightarrow\left(-\frac{1}{16}\right)^{100}>\left(-\frac{1}{2}\right)^{500}\)

Vậy :...(bn tự nói nhé)