Question

So sanh : 

    1111 phan 3333 va 4.9-4.6 phan 8.5+ 4.2

 Giup minh nha !!!

Answer 1

\(\frac{1111}{3333}=\frac{1}{3}\)và \(\frac{4.9-4.6}{8.5+4.2}=\frac{12}{48}\)\(=\frac{1}{4}\)

vậy =>\(\frac{1111}{3333}\)\(>\frac{4.9-4.6}{8.5+4.2}\)

​hok tốt

Answer 2

so sánh \(\frac{1111}{3333}\)và \(\frac{4.9-4.6}{8.5+4.2}\)

ta có \(\frac{4.9-4.6}{8.5+4.2}\) =   \(\frac{12}{48}\)  

 \(\frac{12}{48}\)= 1 - \(\frac{36}{48}\)= 1- \(\frac{3}{4}\) 

\(\frac{1111}{3333}\) =1-\(\frac{2222}{3333}\) = 1- \(\frac{2}{3}\) 

\(\frac{3}{4}\) = 1  --\(\frac{1}{4}\) ; \(\frac{2}{3}\)  = 1 -- \(\frac{1}{3}\)  ; vì \(\frac{1}{4}\)  <  \(\frac{1}{3}\)   nên  1- \(\frac{1}{4}\)  > 1-\(\frac{1}{3}\)  => \(\frac{3}{4}\)  > \(\frac{2}{3}\) 

vì   \(\frac{2}{3}\)  <  \(\frac{3}{4}\)  nên 1 -  \(\frac{2}{3}\)  > 1- \(\frac{3}{4}\)  hay \(\frac{1111}{3333}\) > \(\frac{4.9-4.6}{8.5+4.2}\)