Question

so nguyen duong n thoa man (3n+14):(n+1)

Answer 1

Ta co:

(3n+14):(n+1)

=>(3n+3+11):(n+1)

=>[3(n+1)+11]:(n+1)

Ma 3(n+1):(n+1)

Nen 11:(n+1)

=>(n+1) thuoc Ư(11)

=>(n+1) thuoc {1;11}

Ta co bang sau:

n+1	1	11
n	0	10

Ma n la so nguyen duong nen n=10

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