<=>(3x-4)^5-(3x-4)^7=0
<=>(3x-4)^5-(3x-4)^5.(3x-4)^2=0
<=>(3x-4)^5.[1-(3x-4)^2]=0
<=>(3x-4)^5=0<=>3x=4<=>x=4/3(loại)
Hoặc 1-(3x-4)^2=0<=>(3x-4)^2=1<=>3x-4=1 hoặc 3x-4=-1<=>x=1 thoả mãn
vậy x=1
\(\left(3x-4\right)^7-\left(3x-4\right)^5=0\)
\(\Rightarrow\left(3x-4\right)^2=0\)
\(\Leftrightarrow3x-4=0\)
\(x=\frac{4}{3}\)
ap dung t/c; 1n = 0 ta có;
3x-4 = 1
x = 5/3
hoc toan la phai nam chac kien thuc co ban mk gop y vay thoi
xin loi 1n = 1 hau dau viet voi nhung bai lam thi dung roi hjhj
