Ta có : \(\frac{5\cdot2+6\cdot5+9\cdot n+10\cdot1}{2+5+n+1}=6,8\)
\(\Leftrightarrow\frac{10+30+9n+10}{2+5+n+1}=\frac{34}{5}\)
\(\Leftrightarrow\frac{50+9n}{8+n}=\frac{34}{5}\)
\(\Leftrightarrow5\left(50+9n\right)=34\left(8+n\right)\)
\(\Leftrightarrow250+45n=272+34n\)
\(\Leftrightarrow11n=22\)
\(\Leftrightarrow n=2\)
Vậy n = 2