a) ta có: \(\frac{-5}{6}=\frac{-10}{12};\frac{-3}{4}=\frac{-9}{12}\)
\(\frac{7}{8}=\frac{357}{408};\frac{7}{24}=\frac{119}{408};\frac{16}{17}=\frac{384}{408};\frac{2}{3}=\frac{272}{408}\)
\(\Rightarrow\frac{-10}{12}< \frac{-9}{12}< \frac{119}{408}< \frac{272}{408}< \frac{357}{408}< \frac{384}{408}\)
\(\Rightarrow\frac{-5}{6}< \frac{-3}{4}< \frac{7}{24}< \frac{2}{3}< \frac{7}{8}< \frac{16}{17}\)
b) ta có: \(\frac{205}{107}=1\frac{98}{107}>1\)\(\frac{-5}{8};\frac{7}{10};\frac{-16}{19};\frac{20}{26}=\frac{10}{13};\frac{214}{315}< 1\)
ta có: \(\frac{-5}{8}=\frac{-95}{152};\frac{-16}{19}=\frac{-128}{152}\)
\(\frac{7}{10}=\frac{5733}{8190};\frac{20}{26}=\frac{10}{13}=\frac{6300}{8190};\frac{214}{315}=\frac{5564}{8190}\)
\(\Rightarrow\frac{205}{107}>\frac{6300}{8190}>\frac{5733}{8190}>\frac{5564}{8190}>\frac{-95}{152}>\frac{-128}{152}\)
=> ...
