Question

S=\(3^0+3^1+3^2+......+3^{2016}+3^{2017}\)

Answer 1

S=3^2034114 mở sách lớp 6 ra mà xem nha !!! ^_^

Answer 2

\(S=3^0+3^1+3^2+....+3^{2016}+3^{2017}\)

\(3S=3\left(3^0+3^1+3^2+...+3^{2016}+3^{2017}\right)\)

\(3S=3+3^2+3^3+...+3^{2017}+3^{2018}\)

\(3S-S=3^{2018}-3^0\)

\(=>2S=3^{2018}-3^0\)

\(=>S=\frac{3^{2018}-3^0}{2}\)