Question

S= \(\frac{1}{50}+\frac{1}{51}+\frac{1}{52}+...+\frac{1}{98}+\frac{1}{99}\). So sánh S với \(\frac{1}{2}\)

Answer 1

S = \(\frac{1}{50}+\frac{1}{51}+...+\frac{1}{99}>\frac{1}{100}+\frac{1}{100}+\frac{1}{100}+...+\frac{1}{100}=\frac{1}{100}.50=\frac{1}{2}\)

Kết luận vậy S > 1/2

Answer 2

S=1/2

Answer 3

S>\(\frac{1}{2}\)

Answer 4

S = 1/50 + 1/51 + ... + 1/99 > 1/100 + 1/100 + 1/100 + ... + 1/100 = 1/100.50 = 1/2

Answer 5

s=1/50+1/51+1/99>1/100+1/100+1/100+1/100+...+1/100=1/100.50=1/2

Answer 6

\(S=\frac{1}{50}+\frac{1}{51}+...+\frac{1}{99}\)

Vì \(\frac{1}{99}>\frac{1}{100}\)

\(\Rightarrow S>\frac{1}{100}.50=\frac{1}{2}\)

=> ĐPCm