S = 1 + 2 + 22 + 23 + 24 + 25 + 26 + 27
S = (1+2)+(22+23)+(24+25)+(26+27)
S = 3 + 22(1+2)+24(1+2)+26(1+2)
S = 3 + 22.3 + 24.3 + 26.3
S = 3(22+24+26+1)
=> S chia hết 3
k tui nha. Tui là ARMY nè. Bias của tui là Chây Hốp
S= 1 + 2 + 22 + 23 + 24 + 25 + 26+ 27
Chứng tỏ S chia hết cho 3
S = 3 + 22(2+1) +...+26(2+1)
S = (3 + 22.3+...+26.3) chia hết cho 3
=> S chia hết cho 3
\(S=1+2+2^2+........+2^7\)
\(\Leftrightarrow S=\left(1+2\right)+\left(2^2+2^3\right)+..........+\left(2^6+2^7\right)\)
\(\Leftrightarrow S=1\left(1+2\right)+2^2\left(1+2\right)+.....+2^6\left(1+2\right)\)
\(\Leftrightarrow S=1.3+2^2.3+........+2^6.3\)
\(\Leftrightarrow S=3\left(1+2^2+.........+2^6\right)⋮3\left(đpcm\right)\)
S=(1+2)+(22+23)+(24+25)+(26+27)
S=3+(1+2)*22+(1+3)*24+(1+2)*26
S=3*1+3*22+3*24+3*26
S=3*(1+22+24+26) chia hết cho 3
=>S chia hết cho 3
S = ( 1 + 2 ) + ( 22 + 23 ) + ( 24 + 25) + ( 26 + 27)
S = 1.2 + 2.1 + 22 . 1 + 22 . 2 + 24 . 1 + 24 . 2 + 26 . 1 + 26 . 2
S = 1 . (1+2)+22.(1+2)+24.(1+2) + 26.(1+2)
S = 1.3 + 22 . 3 + 24 . 3 + 26 . 3
S = 3.(1+22 + 24+26)
=> S chia hết cho 3
\(S=1+2+2^2+2^3+2^4+2^5+2^6+2^7\)
\(2S=2+2^2+2^3+2^4+2^5+2^6+2^7+2^8\)
\(S=2S-S=2+2^2+2^3+2^4+2^5+2^6+2^7+2^8-(1+2+2^2+2^3+2^4+2^5+2^6+2^7)\)
\(=>S=2^8-1=(2^4)^2 -1^2=(2^4-1).(2^4+1)=(16-1).(2^4+1)=15.(2^4+1)=3.5.(2^4+1)\)
=> S chia hết cho 3.
S = 1 + 2 + 22 + 23 + 24 + 25 + 26 +27
= ( 1 + 2 ) + ( 22 + 23 ) + ( 24 + 25 ) + ( 26 + 27 )
= ( 1 + 2 ) + 22( 1 + 2 ) + 24( 1 + 2 ) + 26( 1 + 2 )
= ( 1 + 2 )(1 + 22 + 24 + 26 ) = 3.( 1 + 22 + 24 + 26 ) chia hết cho 3