Question

rút gọn\(\sqrt{2018^2+2019^2+2018^2.2019^2}\)

Answer 1

Đây bạn :V

Ta có: \(\sqrt{2018^2+2019^2+2018^2+2019^2}\)

\(=2018+2019+2018+2019\)

\(=2.2018+2.2019\)

\(=2.\left(2018+2019\right)\)

\(=2.4073\)

\(=8047\)

Chúc bạn học tốt:))

Answer 2

Đặt \(2018=a\)

\(\Rightarrow\sqrt{2018^2+2019^2+2018^2.2019^2}=\sqrt{a^2+\left(a+1\right)^2+a^2.\left(a+1\right)^2}\)

\(=\sqrt{a^4+2a^3+3a^2+2a+1}=\sqrt{\left(a^2+a+1\right)^2}\)

\(=a^2+a+1=2018^2+2018+1\)

Answer 3

Nhầm thôi mà