Ta có
• A=1+34+38+312
=>34.A=34+38+312+316
<=>81.A-A=316-1
<=>A=(316-1)/80=538084
•B=1+32+34+36+38+310+312+314
=>32.B=32+34+36+38+310+312+314+316
<=>8.B=316-1
<=>B=(316-1)/8=53808400
Vậy Q=A/B=538084/53808400=1/100=0.01
Sửa lại:
B=5380840
=>Q=1/10
Rút gọn: \(A=\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
Rút gọn :
Q=\(\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
Rút gọn
1+3^4+3^8+3^12/1+3^2+3^4+3^6+3^8+3^10+3^12+3^14
Rút gọn biểu thức
A=\(\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
Giúp mình với ạ. Cảm ơn mọi người nhiều
Rút gọn các biểu thức sau :\(\frac{4^{10}+8^4}{4^5+8^6}\)
\(\frac{1+3^4+3^8+3^{12}}{1+3+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
\(B=\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
a,\(B=\frac{4^{10}+8^4}{4^5+8^6}\)
b,\(C=\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
Tính B,biết:
B=\(\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
Rút gọn:
A = \(\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+..+3^{14}}\)
