Các câu hỏi tương tự
Rút gọn: \(\frac{\sqrt{1+2\sqrt{5\sqrt{\text{7}}-13}}-\sqrt{\sqrt{\text{7}}-2}}{\sqrt{3}-\sqrt{\text{7}}}-\sqrt{\frac{2}{3-\sqrt{5}}}\)
\(\text{Rút gọn biểu thức}\)
\(P=\sqrt{x}+\frac{\sqrt[3]{2-\sqrt{3}}.\sqrt[6]{7-4\sqrt{3}}-x}{\sqrt[4]{9-4\sqrt{5}}.\sqrt{2+\sqrt{5}}+\sqrt{x}}\)
\(\frac{1}{\sqrt{1}-\sqrt{2}}-\frac{1}{\sqrt{2}-\sqrt{3}}+\frac{1}{\sqrt{3}-\sqrt{4}}-\frac{1}{\sqrt{4}-\sqrt{5}}+\frac{1}{\sqrt{5}-\sqrt{6}}-\frac{1}{\sqrt{6}-\sqrt{7}}+\frac{1}{\sqrt{7}-\sqrt{8}}-\frac{1}{\sqrt{8}-\sqrt{9}}\)
RUT GON
Bài 1 Rút gọn và tínha, sqrt{frac{sqrt{a}-1}{sqrt{b}+1}}:sqrt{frac{sqrt{b}-1}{sqrt{a}+1}}với a7.25;b3.25b,sqrt{15text{a}^2-8text{a}sqrt{15}+16} với asqrt{frac{3}{5}}+sqrt{frac{5}{3}}c,sqrt{10text{a}^2-4text{a}sqrt{10}+4}với asqrt{frac{2}{5}}+sqrt{frac{5}{2}}d,sqrt{a^2+2text{a}sqrt{a^2-1}}-sqrt{a^2-2sqrt{a^2-1}}vtext{ới}asqrt{5}
Đọc tiếp
Bài 1 Rút gọn và tính
a, \(\sqrt{\frac{\sqrt{a}-1}{\sqrt{b}+1}}:\sqrt{\frac{\sqrt{b}-1}{\sqrt{a}+1}}\)với a=7.25;b=3.25
b,\(\sqrt{15\text{a}^2-8\text{a}\sqrt{15}+16}\) với \(a=\sqrt{\frac{3}{5}}+\sqrt{\frac{5}{3}}\)
c,\(\sqrt{10\text{a}^2-4\text{a}\sqrt{10}+4}\)với \(a=\sqrt{\frac{2}{5}}+\sqrt{\frac{5}{2}}\)
d,\(\sqrt{a^2+2\text{a}\sqrt{a^2-1}}-\sqrt{a^2-2\sqrt{a^2-1}}v\text{ới}\)\(a=\sqrt{5}\)
help me !
tính S = \(\frac{1}{3+\sqrt{3}}+\frac{1}{3\sqrt{5}+5\sqrt{3}}+\frac{1}{5\sqrt{7}+\sqrt{5}7}+.....+\frac{1}{101\sqrt{103}+103\sqrt{101}}\text{ [}\)!
text{Rút gọn các căn thức sau:}sqrt{frac{4}{left(2-sqrt{5}right)^2}}-sqrt{frac{4}{left(2+sqrt{5}right)^2}}left(2sqrt{8}+3sqrt{5}-7sqrt{2}right)left(sqrt{72}-5sqrt{20}-2sqrt{2}right)sqrt{frac{2-sqrt{3}}{2}}+frac{1-sqrt{3}}{2}sqrt{3+2sqrt{2}}+sqrt{6-4sqrt{4}}K lm tắt nhé !
Đọc tiếp
\(\text{Rút gọn các căn thức sau:}\)
\(\sqrt{\frac{4}{\left(2-\sqrt{5}\right)^2}}-\sqrt{\frac{4}{\left(2+\sqrt{5}\right)^2}}\)
\(\left(2\sqrt{8}+3\sqrt{5}-7\sqrt{2}\right)\left(\sqrt{72}-5\sqrt{20}-2\sqrt{2}\right)\)
\(\sqrt{\frac{2-\sqrt{3}}{2}}+\frac{1-\sqrt{3}}{2}\)
\(\sqrt{3+2\sqrt{2}}+\sqrt{6-4\sqrt{4}}\)
K lm tắt nhé !
GIÚP EM ĐI ẠTÍNH:frac{3-sqrt{6+sqrt{3+sqrt{6+sqrt{3}}}}}{3-sqrt{3+sqrt{6+sqrt{3}}}}+frac{2+sqrt{6+sqrt{3+sqrt{6+sqrt{3}}}}}{3+sqrt{6+sqrt{3+sqrt{6+sqrt{3}}}}}frac{1+frac{sqrt{3}}{2}}{1+sqrt{1+frac{sqrt{3}}{2}}}+frac{1-frac{sqrt{3}}{2}}{1-sqrt{1-frac{sqrt{3}}{2}}}frac{1}{sqrt{frac{5}{13}}+sqrt{frac{5}{7}}+1}+frac{1}{sqrt{frac{7}{5}}+sqrt{frac{7}{13}}+1}+frac{1}{sqrt{1frac{6}{7}}+1+sqrt{2frac{3}{5}}}RÚT GỌNsqrt{left(x-1right)^2}-x với x lớn hơn 1GIẢI PHƯƠNG TRÌNHsqrt{x^2-3x+2}+sqrt{x^2-4x+3}0
Đọc tiếp
GIÚP EM ĐI Ạ
TÍNH:
\(\frac{3-\sqrt{6+\sqrt{3+\sqrt{6+\sqrt{3}}}}}{3-\sqrt{3+\sqrt{6+\sqrt{3}}}}+\frac{2+\sqrt{6+\sqrt{3+\sqrt{6+\sqrt{3}}}}}{3+\sqrt{6+\sqrt{3+\sqrt{6+\sqrt{3}}}}}\)
\(\frac{1+\frac{\sqrt{3}}{2}}{1+\sqrt{1+\frac{\sqrt{3}}{2}}}+\frac{1-\frac{\sqrt{3}}{2}}{1-\sqrt{1-\frac{\sqrt{3}}{2}}}\)
\(\frac{1}{\sqrt{\frac{5}{13}}+\sqrt{\frac{5}{7}}+1}+\frac{1}{\sqrt{\frac{7}{5}}+\sqrt{\frac{7}{13}}+1}+\frac{1}{\sqrt{1\frac{6}{7}}+1+\sqrt{2\frac{3}{5}}}\)
RÚT GỌN
\(\sqrt{\left(x-1\right)^2}-x\) với x lớn hơn 1
GIẢI PHƯƠNG TRÌNH
\(\sqrt{x^2-3x+2}+\sqrt{x^2-4x+3}=0\)
a) frac{2sqrt{5}-4sqrt{10}}{3sqrt{10}}b)frac{6sqrt{6}-2sqrt{12}+3-sqrt{2}}{2sqrt{6}+1}c)frac{sqrt{3left(3-sqrt{11}right)^2}}{sqrt{6}left(3-sqrt{11}right)}d)frac{5sqrt{7}-4sqrt{35}+7sqrt{5}}{sqrt{35}}e) left(sqrt{3}-1right)sqrt{2sqrt{19+8sqrt{3}-4}}g) sqrt{47+sqrt{5}}.sqrt{7-sqrt{2+sqrt{5}}.}sqrt{7+sqrt{2+sqrt{5}}}
Đọc tiếp
a) \(\frac{2\sqrt{5}-4\sqrt{10}}{3\sqrt{10}}\)
b)\(\frac{6\sqrt{6}-2\sqrt{12}+3-\sqrt{2}}{2\sqrt{6}+1}\)
c)\(\frac{\sqrt{3\left(3-\sqrt{11}\right)^2}}{\sqrt{6}\left(3-\sqrt{11}\right)}\)
d)\(\frac{5\sqrt{7}-4\sqrt{35}+7\sqrt{5}}{\sqrt{35}}\)
e) \(\left(\sqrt{3}-1\right)\sqrt{2\sqrt{19+8\sqrt{3}-4}}\)
g) \(\sqrt{47+\sqrt{5}}.\sqrt{7-\sqrt{2+\sqrt{5}}.}\sqrt{7+\sqrt{2+\sqrt{5}}}\)
1. CHỨNG MINH ĐẲNG THỨCa. text{[}3+2sqrt{6}-sqrt{33}text{]}cdottext{[}sqrt{22}+sqrt{6}+4text{]}24b. text{[}frac{1}{5-2sqrt{6}}+frac{2}{5+2sqrt{6}}text{]}cdottext{[}15+2sqrt{6}text{]}c.text{[}frac{4}{3}cdotsqrt{3}+sqrt{2}+sqrt{3frac{1}{3}}text{]}cdottext{[}sqrt{1,2}+sqrt{2}-4sqrt{frac{1}{5}}text{]}4d. sqrt{text{[}1-sqrt{1989}text{]}^2}cdotsqrt{1990+2sqrt{1989}}1988e. frac{a-sqrt{ab}+b}{asqrt{a}+bsqrt{b}}-frac{1}{a-b}frac{sqrt{a}-sqrt{b}-1}{a-b}với a0;b0và ane b
Đọc tiếp
1. CHỨNG MINH ĐẲNG THỨC
a. \(\text{[}3+2\sqrt{6}-\sqrt{33}\text{]}\cdot\text{[}\sqrt{22}+\sqrt{6}+4\text{]}=24\)
b. \(\text{[}\frac{1}{5-2\sqrt{6}}+\frac{2}{5+2\sqrt{6}}\text{]}\cdot\text{[}15+2\sqrt{6}\text{]}\)
c.\(\text{[}\frac{4}{3}\cdot\sqrt{3}+\sqrt{2}+\sqrt{3\frac{1}{3}}\text{]}\cdot\text{[}\sqrt{1,2}+\sqrt{2}-4\sqrt{\frac{1}{5}}\text{]}=4\)
d. \(\sqrt{\text{[}1-\sqrt{1989}\text{]}^2}\cdot\sqrt{1990+2\sqrt{1989}}=1988\)
e. \(\frac{a-\sqrt{ab}+b}{a\sqrt{a}+b\sqrt{b}}-\frac{1}{a-b}=\frac{\sqrt{a}-\sqrt{b}-1}{a-b}\)với \(a>0;b>0\)và \(a\ne b\)