Question

rút gọn:\(\frac{\left(\frac{-1}{3}\right)^2-\left(\frac{3}{4}\right)^3.\left(-2\right)^2}{2.\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}\)

Answer 1

\(\frac{\left(-\frac{1}{3}\right)^2-\left(\frac{3}{4}\right)^3.\left(-2\right)^2}{2.\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}=\frac{\frac{1}{9}-\frac{27}{64}.4}{-2+\frac{9}{16}-\frac{3}{8}}=\frac{\frac{1}{9}-\frac{27}{16}}{-2+\frac{3}{16}}\)

\(=\frac{\frac{16}{144}-\frac{243}{144}}{-\frac{32}{16}+\frac{3}{16}}=\frac{\frac{-227}{144}}{\frac{-29}{16}}=\frac{-227}{144}.\frac{-16}{29}\)

\(=\frac{227.16}{144.29}=\frac{227.1}{9.29}=\frac{227}{261}\)

Đáp số: \(\frac{227}{261}\)