Rút gọn các biểu thức
\(B=\frac{9\sqrt{5}+3\sqrt{27}}{\sqrt{5}+\sqrt{3}} \)
\(C=\frac{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+4}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\)
\(D=\frac{3\sqrt{8}-2\sqrt{12}+20}{3\sqrt{18}-2\sqrt{27}+\sqrt{45}}\)
Rút gọn a) \(\frac{3\sqrt{8}-2\sqrt{12}+\sqrt{40}}{3\sqrt{18}-2\sqrt{27}+\sqrt{45}}\)
b) \(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
c) \(\sqrt{2+\sqrt{3}}+\sqrt{2+\sqrt{2+\sqrt{3}}}+\sqrt{2+\sqrt{2+\sqrt{2+\sqrt{3}}}}+\sqrt{2-\sqrt{2+\sqrt{2+\sqrt{3}}}}\)
bài 1 : rút gọn
\(A=\frac{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+4}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\)
\(B=\frac{3\sqrt{8}-2\sqrt{12}+20}{3\sqrt{18}-2\sqrt{27}+\sqrt{45}}\)
\(\frac{\sqrt{6+2\sqrt{5}}}{\sqrt{5}+1}-\sqrt{3-\sqrt{5}}\)
các bạn làm hộ mình với ạ , mình đg cần gấp
rút gọn
\(y=\frac{3\sqrt{8}-2\sqrt[]{12}+\sqrt{20}}{3\sqrt{18}-2\sqrt{27}+\sqrt{15}}\)
Rút gọn biểu thức
I=(2\(\sqrt{3}\)-5\(\sqrt{27}\)+4\(\sqrt{12}\)):\(\sqrt{3}\)
K=\(\sqrt{125}\)-4\(\sqrt{45}\)+3\(\sqrt{20}\)-\(\sqrt{80}\)
L=2\(\sqrt{9}\)+\(\sqrt{25}\)-5\(\sqrt{4}\)
N=2\(\sqrt{32}\)-5\(\sqrt{27}\)-4\(\sqrt{8}\)+3\(\sqrt{75}\)
O=2\(\sqrt{3.5^2}\)-3\(\sqrt{3.2^2}\)+\(\sqrt{3.3^2}\)
rút gọn biểu thức
E=2\(\sqrt{3}\)+3\(\sqrt{27}\)-\(\sqrt{300}\)
F=3\(\sqrt{2}\)+4\(\sqrt{18}\)
G=2\(\sqrt{3}\)-4\(\sqrt{27}\)+5\(\sqrt{48}\)
H=(3\(\sqrt{50}\)-5\(\sqrt{18}\)+3\(\sqrt{8}\))\(\sqrt{2}\)
1. Tính: \(\left[\sqrt{12}+3\sqrt{15}-4\sqrt{135}\right]\cdot\sqrt{3}\)
\(\sqrt{252}-\sqrt{700}+\sqrt{1008}-\sqrt{448}\)
\(2\sqrt{40\cdot\sqrt{12}}-2\sqrt{\sqrt{75}}-3\sqrt{5\sqrt{48}}\)
2. Rút gọn biểu thức: \(\frac{\sqrt{6}+\sqrt{4}}{2\sqrt{3}+\sqrt{28}}\)
\(\frac{9\sqrt{5}+3\sqrt{27}}{\sqrt{5}+\sqrt{3}}\)
\(\frac{3\sqrt{8}-2\sqrt{12}+\sqrt{20}}{3\sqrt{18}-2\sqrt{27}+\sqrt{45}}\)
Rút gọn
a)\(\frac{\sqrt{3}+\sqrt{27}}{2\sqrt{3}+\sqrt{18}}\) b) \(\frac{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+\sqrt{16}}{2+\sqrt{2}+\sqrt{3}}\)
rút gọn biểu thức
A=2015+\(\sqrt{36}\)-\(\sqrt{25}\)
B=5\(\sqrt{8}\)+\(\sqrt{50}\)-2\(\sqrt{18}\)
C=\(\sqrt{27}\)-2\(\sqrt{12}\)-\(\sqrt{75}\)
D=\(\sqrt{12}\)+\(\sqrt{27}\)-\(\sqrt{48}\)