Question

Rút gọn

\(B=\frac{x+2}{x+3}.\frac{x+3}{x+4}:\frac{x+4}{x+5}.\frac{\left(x+4\right)^2}{x+5}\)

 

Answer 1

\(B=\frac{x+2}{x+3}\cdot\frac{x+3}{x+4}:\frac{x+4}{x+5}\cdot\frac{\left(x+4\right)^2}{x+5}\)

\(B=\frac{x+2}{x+3}\cdot\frac{x+3}{x+4}\cdot\frac{x+5}{x+4}\cdot\frac{\left(x+4\right)^2}{x+5}\)

\(B=\frac{\left(x+2\right)\left(x+3\right)\left(x+5\right)\left(x+4\right)^2}{\left(x+3\right)\left(x+4\right)\left(x+4\right)\left(x+5\right)}\)

\(B=\frac{x+2}{1}\)

\(B=x+2\)

Answer 2

\(B=\frac{x+2}{x+3}.\frac{x+3}{x+4}.\frac{x+4}{x+5}.\frac{\left(x+4\right)^2}{x+5}\)

\(B=\frac{\left(x+2\right)\left(x+3\right)\left(x+4\right)\left(x+4\right)^2}{\left(x+3\right)\left(x+4\right)\left(x+5\right)\left(x+5\right)}\)

\(B=\frac{\left(x+2\right)\left(x+4\right)^2}{\left(x+5\right)^2}\)

Answer 3

a kudo shinichi có dấu chia kìa :))

Answer 4

\(\left(\frac{x+2}{x+3}\right)\left(\frac{x+3}{x+4}\right):\left(\frac{x+4}{x+5}\right).\left(\frac{\left(x+4\right)^2}{x+5}\right)=\frac{\left(x+2\right)\left[\left(x+5\right)\left(x+4\right)\right]\left(x+4\right)}{\left(x+4\right)\left(x+4\right)\left(x+5\right)}=\left(x+2\right)\)

Answer 5

Bonking: ừ nhỉ.

làm nhầm.

B tham khảo bài Bonking nhé =))

Answer 6

Các bạn giúp mình thêm bài này với.  https://olm.vn//hoi-dap/detail/200689495465.html?auto=1