Question

Rút gọn:

A=\(\sqrt{\left(x+3\right)^2}\) - \(\frac{\sqrt{x^2-6x+9}}{x+3}\)

Answer 1

Ta có : \(A=\sqrt{\left(x+3\right)^2}-\frac{\sqrt{x^2-6x+9}}{x+3}\)

\(\Rightarrow A=\left(x+3\right)-\frac{\left(x-3\right)^2}{\left(x+3\right)}\)

\(\Rightarrow A=\frac{\left(x+3\right)^2}{\left(x+3\right)}-\frac{\left(x-3\right)^2}{\left(x+3\right)}\)

\(\Rightarrow A=\frac{\left(x+3\right)^2-\left(x-3\right)^2}{\left(x+3\right)}\)

\(\Rightarrow A=\frac{\left(x+3+x-3\right)\left(x+3-x+3\right)}{\left(x+3\right)}\)

\(\Rightarrow A=\frac{18x}{\left(x+3\right)}\)

Answer 2

Mình quên ghi điều kiện mất là x<-3 nhé

Mấy bạn làm lại giúp mình

Mình cảm ơn  :D