31 tháng 3 2017 lúc 17:20
Các câu hỏi tương tự
CMR:
a, \(100-\left(1+\frac{1}{2}+\frac{1}{3}+..+\frac{1}{100}\right)=\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+..+\frac{99}{100}\)
b, \(\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{199}\right)-\left(\frac{1}{2}+\frac{1}{4}+..+\frac{1}{200}\right)=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
Giải nhanh giùm mình nhé!!!!!!!!!!!!!!
tìm N:M biết
\(M=\frac{1}{2}-\frac{3}{4}+\frac{5}{6}-\frac{7}{8}+...+\frac{197}{198}-\frac{199}{200}\)
\(N=\frac{1}{51}+\frac{1}{52}+...+\frac{1}{100}\)
help me
Cho M=\(\frac{1}{2}-\frac{3}{4}+\frac{5}{6}-\frac{7}{8}+...+\frac{197}{198}-\frac{199}{200}\)
N=\(\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+...+\frac{1}{100}\)
Tính N:M
Cho \(M=\frac{1}{2}-\frac{3}{4}+\frac{5}{6}-\frac{7}{8}+...+\frac{197}{198}-\frac{199}{200}\) và \(N=\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+....+\frac{1}{100}\)
Tính N : M
Tính: \(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{200}}{\frac{1}{199}+\frac{2}{198}+\frac{3}{197}+...+\frac{198}{2}+\frac{199}{1}}\)
tính
\(\frac{\frac{1}{2}+\frac{1}{3}+....+\frac{1}{200}}{\frac{1}{199}+\frac{2}{198}+.....+\frac{198}{1}+\frac{199}{1}}\)
\(\left(x-20\right)\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{200}}{\frac{1}{199}+\frac{2}{198}+\frac{3}{197}+...+\frac{198}{2}+\frac{199}{1}}=\frac{1}{2000}\)
Cho A=\(\frac{1}{2}-\frac{3}{4}+\frac{5}{6}-\frac{7}{8}+...+\frac{197}{198}-\frac{199}{200}\)
B=\(\frac{1}{51}+\frac{1}{52}+...+\frac{1}{100}\)
Tính \(\frac{B}{A}\)
Chứng minh rằng
a)\(\frac{5}{8}<\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{200}<\frac{3}{4}\)
b)\(\frac{1}{4}+\frac{1}{6}+\frac{1}{16}+...+\frac{1}{10000}<\frac{3}{4}\)
c)(\(\frac{1}{2}.\frac{3}{4}.\frac{5}{6}....\frac{199}{200}\))2 <\(\frac{1}{201}\)
d)\(50<1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}...+\frac{1}{2^{100}-1}<100\)