Question

Rut gon:

a,   10^{n + 1} - 6 . 10ⁿ

^b, 90 . 10ⁿ - 10^{n + 2} + 10^{n +1}

Answer 1

a)10ⁿ⁺¹-6.10ⁿ

=10ⁿ.10-6.10ⁿ

=10ⁿ(10-6)

=10ⁿ.4

b)90.10ⁿ-10ⁿ⁺²+10ⁿ⁺¹

=90.10ⁿ-10ⁿ.100+10^n₊10

=10ⁿ(90-100+10)

=10ⁿ.0

=0

Answer 2

a, \(10^{n+1}-6.10^n\)

= \(10^n.10-6.10^n\)

=\(10^n.\left(10-6\right)\)

=\(10^n.4\)

b, \(90.10^n-10^{n+2}-10^{n+1}\)

= \(90.10^n-10^n.10^2-10^n.10\)

= \(10^n.\left(90-10^2-10\right)\)

= \(10^n.\left(-20\right)\)

nhớ k cho mik nha!!!!!!!!!!!!!