TH1 : \(x< -2\)
\(\left|x+1\right|+\left|x+2\right|+\left|x-3\right|=-\left(x+1\right)-\left(x+2\right)+\left(3-x\right)\)
\(=-x-1-x-2+3-x=-3x\)
TH2: \(-2\le x< -1\)
\(\left|x+1\right|+\left|x+2\right|+\left|x-3\right|=-\left(x+1\right)+\left(x+2\right)+\left(3-x\right)\)
\(=-x-1+x+2+3-x\)
\(=4-x\)
TH3: \(-1\le x< 3\)
\(\left|x+1\right|+\left|x+2\right|+\left|x-3\right|=\left(x+1\right)+\left(x+2\right)+\left(3-x\right)\)
\(=x+1+x+2+3-x=6+x\)
TH4: \(x\ge3\)
\(\left|x+1\right|+\left|x+2\right|+\left|x-3\right|=\left(x+1\right)+\left(x+2\right)+\left(x-3\right)\)
\(=3x\)
=x+1+x+2+x-3
=x+(1+2)-3
=x+3-3
=x+0
nhớ k cho mình nha
