Question

     Rút gọn phân thức:

(a^2+b^2+c^2)(a+b+c)+(ab+ac+bc)/(a+b+c)^2-(ab+bc+ca) 

Answer 1

Sửa đề:

\(\frac{\left(a^2+b^2+c^2\right)\left(a+b+c\right)+\left(ab+bc+ca\right)\left(a+b+c\right)}{\left(a+b+c\right)^2-\left(ab+bc+ca\right)}\)

\(=\frac{\left(a^2+b^2+c^2+ab+bc+ca\right)\left(a+b+c\right)}{a^2+b^2+c^2+2ab+2bc+2ca-\left(ab+bc+ca\right)}\)

\(=\frac{\left(a^2+b^2+c^2+ab+bc+ca\right)\left(a+b+c\right)}{a^2+b^2+c^2+ab+bc+ca}\)

\(=a+b+c\left(a^2+b^2+c^2+ab+bc+ca\ne0\right)\)

Answer 2

cảm ơn anh để em xem lại 

Answer 3

(a^2+b^2+c^2)(a+b+c)+(ab+ac+bc)^2/(a+b+c)^2-(ab+bc+ca) có đúng đề ko ạ