Question

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2ax mũ 2 - 4ax + 2a / 5b - 5bx mũ 2

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Answer 1

\(\frac{2ax^2-4ax+2a}{5b-5bx^2}\)

\(=-\frac{2a\left(x-1\right)^2}{5b\left(x+1\right)\left(x-1\right)}\)

\(=-\frac{2a\left(x-1\right)}{5b\left(x+1\right)}\)