a)\(\frac{25-7.25}{6.15}\)
\(=\frac{25.\left(1-7\right)}{6.15}\)
\(=\frac{25.\left(-6\right)}{6.15}\)
\(=\frac{5.\left(-1\right)}{1.3}\)
\(=\frac{-5}{3}\)
b)\(\frac{15.11-15}{25.\left(-10\right)}\)
\(=\frac{15.\left(11-1\right)}{25.\left(-10\right)}\)
\(=\frac{15.10}{25.\left(-10\right)}\)
\(=\frac{3.1}{5.\left(-1\right)}\)
\(=\frac{-3}{5}\)
a) \(\frac{25-7.25}{6.15}=\frac{25.1-7.25}{6.15}=\frac{25.\left(1-7\right)}{6.15}=\frac{5.5.\left(-6\right)}{2.3.3.5}=\frac{5.5.3.\left(-2\right)}{2.3.3.5}=\frac{-5}{3}\)
b) \(\frac{15.11-15}{25.\left(-10\right)}=\frac{15.\left(11-1\right)}{25.\left(-10\right)}=\frac{15.10}{25.\left(-10\right)}=\frac{3.5.2.5}{5.5.2.\left(-5\right)}=\frac{3}{-5}\)
\(a,\frac{25-7.25}{6.15}\)
\(=\frac{25.\left(1-7\right)}{6.15}\)
\(=\frac{25.\left(-6\right)}{6.15}\)
\(=\frac{5.\left(-1\right)}{1.3}\)
\(=\frac{-5}{3}\)
\(b,\frac{15.11-15}{25.\left(-10\right)}\)
\(=\frac{15.\left(11-1\right)}{25.\left(-10\right)}\)
\(=\frac{15.10}{25.\left(-10\right)}\)
\(=\frac{3.1}{5.\left(-1\right)}\)
\(=\frac{-3}{5}\)