\(\frac{3^4.2^3-3^4.4}{3^5.3^2-3^5.5}=\frac{3^4.\left(2^3-4\right)}{3^5.\left(3^2-5\right)}=\frac{8-4}{3.\left(9-5\right)}=\frac{4}{3.4}=\frac{1}{3}\)
\(\frac{3^4\cdot2^3-3^4\cdot4}{3^5.3^2-3^5\cdot5}=\frac{3^4\left(8-4\right)}{3^5\left(9-5\right)}=\frac{4}{3\cdot4}=\frac{1}{3}\)