n4+4=n4+4n2+4-4n2=(n^2+2)^2-(2n)^2=(n^2+2n+2)(n^2-2n+2)=((n+1)^2+1)((n-1)^2+1)
=>P =\(\frac{\left(1^2+1\right)\left(3^2+1\right)...\left(2013^2+1\right)\left(2015^2+1\right)}{\left(3^2+1\right)\left(5^2+1\right)...\left(2015^2+1\right)\left(2017^2+1\right)}=\frac{2}{2017^2+1}\)
Rút gọn biểu thức \(P=\frac{\left(2^4+4\right)\left(6^4+4\right)\left(10^4+4\right)...\left(2014^4+4\right)}{\left(4^4+4\right)\left(8^4+4\right)\left(12^4+4\right)..\left(2016^4+4\right)}\)
Bạn nào giải nhanh đúng mình tick cho nha ^ ^.
Rút gọn \(\frac{\left(2^4+4\right)\left(6^4+4\right)\left(10^4+4\right)\left(14^4+4\right)}{\left(4^4+4\right)\left(8^4+4\right)\left(12^4+4\right)\left(16^4+4\right)}\)
1.Chứng minh \(\frac{x^2+y^2-z^2-2zt+2xy-t^2}{x+y-z-t}=\frac{x^2-y^2+z^2}{x-y+z-t}-2zt+2xz-t^2\)
2.Rút gọn X= \(\frac{\left(2^4+4\right)\left(6^4+4\right)\left(10^4+4\right)\left(14^4+4\right)}{\left(4^4+4\right)\left(8^4+4\right)\left(12^4+4\right)\left(16^4+4\right)}\)
Tính : \(\frac{\left(1^4+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)\left(7^4+\frac{1}{4}\right)\left(9^4+\frac{1}{4}\right)\left(11^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right)\left(8^4+\frac{1}{4}\right)\left(10^4+\frac{1}{4}\right)\left(12^4+\frac{1}{4}\right)}\)
Rút gọn
\(A=\frac{\left(1^4+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right).....\left(15^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right).....\left(16^4+\frac{1}{4}\right)}\)
Rút gọn :
\(A=\frac{\left(1+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)...\left(51^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right)...\left(52^4+\frac{1}{4}\right)}\)
Câu hỏi: Rút gọn biểu thức A = \(\frac{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right)....\left(\left(2k\right)^4+\frac{1}{4}\right)}{\left(1^4+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)....\left(\left(2k-1\right)^4+\frac{1}{4}\right)}\) (k thuộc N*)
RÚT GỌN
B= \(\frac{\left(1^4+0,25\right).\left(3^4+0,25\right).\left(5^4+0,25\right)....\left(11^4+0,25\right)}{\left(2^4+0.25\right).\left(4^4+0,25\right).\left(6^4+0,25\right).....\left(12^4+0,25\right)}\)
AI LÀM ĐÚNG CHO 2 TICK LUÔN
0,25 CÁC BẠN CHUYỂN THÀNH 1 PHẦN 4 NHA
\(P=\left(\frac{\left(1^4+4\right)\left(5^4+4\right)\left(9^4+4\right)....\left(21^4+4\right)}{\left(3^4+4\right)\left(7^4+4\right)\left(11^4+4\right).....\left(23^4+4\right)}\right)\). Rút gọn biểu thức
