Question

rút gọn: 

\(\left(a-b\right)^2\left(\sqrt{\frac{a+b}{a-b}}+1\right)\left(\sqrt{\frac{a+b}{a-b}}-1\right)\)1

Answer 1

bỏ số 14 cuối nha mọi ng, mình nhầm

Answer 2

Tớ giải bừa

\(\left(a-b\right)^2\left(\sqrt{\frac{a+b}{a-b}}+1\right)\left(\sqrt{\frac{a+b}{a-b}}-1\right)\)

\(=\left(a-b\right)^2\left(\sqrt{\frac{a+b}{a-b}}\right)^2-1^2\)

\(=\left(a-b\right)^2\left(\frac{a+b}{a-b}-1\right)\)

\(=2ab-2b^2\)

Answer 3

\(\left(a-b\right)^2\left(\sqrt{\frac{a+b}{a-b}}+1\right)\left(\sqrt{\frac{a+b}{a-b}}-1\right)\)

\(=\left(a-b\right)^2\left(\sqrt{\frac{a+b}{a-b}}^2-1\right)\)

\(=\left(a-b\right)^2\left(\left|\frac{a+b}{a-b}\right|-1\right)\)

\(=\left(a-b\right)^2\left(\frac{a+b}{a-b}-1\right)\)(Vì \(\frac{a+b}{a-b}\)nằm trong dấu căn ban đầu)

\(=\frac{\left(a-b\right)^2\left(a+b\right)}{a-b}-\left(a-b\right)^2\)

\(=a^2-b^2-a^2+2ab-b^2\)

\(=2ab-2b^2\)