\(\frac{x^2-9-\left(4x-2\right)\left(x-3\right)}{x^2-6x+9}\)
\(=\frac{\left(x-3\right)\left(x+3\right)-\left(4x-2\right)\left(x-3\right)}{\left(x-3\right)^2}\)
\(=\frac{\left(x-3\right)\left[\left(x+3\right)-\left(4x-2\right)\right]}{\left(x-3\right)^2}\)
\(=\frac{x+3-4x+2}{x-3}\)
\(=\frac{-3x+5}{x-3}\)
Rút gọn các biểu thức sau:
a)\(x+3+\sqrt{x^2-6x+9}\left(x\le3\right)\)
b) \(\sqrt{x^2+4x+4}-\sqrt{x^2}\left(-2\le x\le0\right)\)
c) \(\frac{\sqrt{x^2-2x+1}}{x-1}\left(x>1\right)\)
d) \(\left|x-2\right|+\frac{\sqrt{x^2-4x+4}}{x-2}\left(x< 2\right)\)
Rút gọn:
\(A=\frac{x^2+5x+6+x\sqrt{9-x^2}}{3x-x^2+\left(x+2\right).\sqrt{9-x^2}}\)
\(B=\frac{x^2-5x+6+3\sqrt{x^2-6x+8}}{3x-12+\left(x-3\right).\sqrt{x^2-6x+8}}\)
\(C=\frac{\sqrt{2\sqrt{4-x^2}}.\left(\sqrt{\left(2+x\right)^3}-\sqrt{\left(2-x\right)^3}\right)}{4+\sqrt{4-x^2}}\)
Rút gọn:
\(A=\frac{x^2+5x+6+x\sqrt{9-x^2}}{3x-x^2+\left(x+2\right).\sqrt{9-x^2}}\)
\(B=\frac{x^2-5x+6+3\sqrt{x^2-6x+8}}{3x-12+\left(x-3\right).\sqrt{x^2-6x+8}}\)
\(C=\frac{\sqrt{2\sqrt{4-x^2}}.\left(\sqrt{\left(2+x\right)^3}-\sqrt{\left(2-x\right)^3}\right)}{4+\sqrt{4-x^2}}\)
\(\left(\frac{x-3\sqrt{x}}{x-9}-1\right)\):\(\left(\frac{9-x}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}+\frac{\sqrt{x}-3}{\sqrt{x}-2}-\frac{\sqrt{x}+2}{\sqrt{x}+3}\right)\)rút gọn và tìm gtln
Các bạn giải chi tiết giùm mk nhé . Xin cảm ơn
Bài 1 : Rút gọn A=\(\sqrt[3]{\frac{x^3-3x+\left(x^2-1\right)\sqrt{x^2-4}}{2}}\) + \(\sqrt[3]{\frac{x^3-3x-\left(x^2-1\right)\sqrt{x^2-4}}{2}}\)
Bài 2 : Cho biểu thức : P= \(\frac{x^2-4x-\left(x-1\right)\sqrt{x^2-9}+3}{x^2+4x-\left(x+1\right)\sqrt{x^2-9}+3}\)* \(\sqrt{\frac{x+3}{x-3}}\)với x>3
a> Rút gọn biểu thức P
b> Tìm giá trị lớn nhất của M= \(\frac{2}{P\left(x\right)}+\frac{1-x}{2016}\)
Rút gọn:
a/ \(\sqrt{72a^8\left(x^2-4x+4\right)}\) \(\left(a< 0;x< 2\right)\);
b/ \(\sqrt{40x^6\left(a^2+6x+9\right)}\left(x< 0;a>=-3\right)\)
Rút gọn các biểu thức sau ;
E = \(\dfrac{\left|x-3\right|}{x^2-9}.\left(x^2+6x+9\right)\)
F = \(\dfrac{\sqrt{x}}{\sqrt{x}-5}-\dfrac{10\sqrt{x}}{x-25}-\dfrac{5}{\sqrt{x}+5}\)
Rút gọn:
A=\(\sqrt{\left(x+3\right)^2}\) - \(\frac{\sqrt{x^2-6x+9}}{x+3}\)
\(\left(\frac{x+3\sqrt{x}}{x-9}-1\right):\left(\frac{9-x}{x+\sqrt{x}-6}+\frac{\sqrt{x}-3}{\sqrt{x}-2}-\frac{\sqrt{x}-2}{\sqrt{x}+3}\right)\)
RÚT GỌN GIÙM MK VỚI
