Question

rut gon bthuc

\(\sqrt{98}\)- \(\sqrt{72}\)- 0,5\(\sqrt{8}\)

Answer 1

\(\sqrt{98}-\sqrt{72}-0,5\sqrt{8}.\)

\(=\sqrt{7\cdot7\cdot2}-\sqrt{6\cdot6\cdot2}-0,5\sqrt{2\cdot2\cdot2}\)

\(=7\sqrt{2}-6\sqrt{2}-0,5\cdot2\sqrt{2}\)

\(=7\sqrt{2}-6\sqrt{2}-\sqrt{2}\)

\(=0\)

Answer 2

\(\sqrt{98}-\sqrt{72}-\frac{\sqrt{8}}{2}\)

=\(7\sqrt{2}-6\sqrt{2}-\sqrt{2}\)

\(=0\)