Ý bạn là
\(2^n+3+2^{^{ }n}+2-2^{^{ }n}+1+2^n\)
Giải :
\(A=2^n+3+2^n+2-2^n+1+2^n\)
\(A=\left(2^n+2^n-2^n+2^n\right)+3+1\)
\(A=3\times2^n+3+1\)
\(A=3\times2^n+4\)
Ý bạn là
\(2^n+3+2^{^{ }n}+2-2^{^{ }n}+1+2^n\)
Giải :
\(A=2^n+3+2^n+2-2^n+1+2^n\)
\(A=\left(2^n+2^n-2^n+2^n\right)+3+1\)
\(A=3\times2^n+3+1\)
\(A=3\times2^n+4\)
cho n la so tu nhien co 2 chu so.Tim n biet n+4 va 2n deu la so chinh phuong
thanks truoc nha
tìm số nguyên n sao cho :
1,n^2+2n-4 chia hết cho 11
2,2n^3+n^2+7n+1 chia hết cho 2n -1
3,n^4-2n^3+2n^2-2n+1 chia hết cho n^4-1
So sánh: n-1/n+2 và 2n+1/2n+5
cau 1 ,cho m,n thuoc n va p la so nguyen to thoa man p/m-1=m+n/p
CMRp^2=n+2
cau 2,cho a,b,c thoa man a+b+c=0 CMRab+bc+ca be hon hoac bang 0
cau 3,bay gio la 4 gio 10 phut hoi sau it nhat bao lau thi hai kim dong ho nam doi dien nhau tren mot duong thang
cau 4,so 2^100 viet trong he thap phan tao thanh 1 so hoi so do co bao nhieu chu so
cau 5,cho a,b,c la so do 3 canh cua mot tam giac vuong voi c la so do canh huyen CMRa^2n+b^2n be hon hoac bang c^2n (n la so tu nhien lon hon 0 )
CMR voi moi so tu nhien n thi
A=5^2n+1*2^n+2+3^n+2*2^2n+1 chia het cho 38
tìm n là số nguyên sao cho:a) \(^{n^3-n^2+2n+7⋮n^2+1}\)
b) \(n^4-2n^3+2n^2-2n+1⋮n^2+1\)
tim cac so nguyen n sao cho P=2n -1 / n-1 la so nguyen
Voi n la so nguyen duong ta co:(-1)^2n+1=....
TIM N LA SO NGUYEN SAO CHO
a , 3n +11 chia het cho n
b , 2n - 7 chia het cho n+ 2
c , n2 + 2n + 10 chia het cho n+ 1