g) \(\frac{1489.1490+2978}{1492.1491-2984}\)
\(=\frac{1489.1491-1489+2978}{1492.1491-2984}\)
\(=\frac{1489.1491+1489}{1492.1491-2984}\)
\(=\frac{1492.1491-3.1491+1489}{1492.1491-2984}\)
\(=\frac{1492.1491-2984}{1492.1491-2984}=1\)
h) \(6.134.2+12.163+4.3.203=12.134+12.163+12.203\)
\(=12\left(134+163+203\right)=12.500=12.50.10\)
\(1+3+5+...+99=\left[\frac{99-1}{2}+1\right].\frac{\left(99+1\right)}{2}=50.50=\)
=> \(1+2+3+4+...+99-500=50.50-50.10=50.\left(50-10\right)=50.40\)
=> \(\frac{6.134.2+12.163+4.203.3}{1+3+5+...+97+99-500}=\frac{12.50.10}{40.50}=\frac{120}{40}=3\)