a)A=(a+b-c)+(a-b)-(a-b-c)
=a+b-c+a-b-a+b+c
=(a+a-a)+(b-b+b)-(c-c)
=a+b
b)B=(-a-b+c)+(a+b)
=-a-b+c+a+b
=(-a+a)-(b-b)+c
=0+0+c=c
c)C=-(a+b-c)+(-c)+(-a-b)-(a+b+c)
=-a+b-c-c-a-b-a+b+c
=-(a+a+a)+(b-b+b)-(c+c-c)
=-3a+b-c
d)D=-(-a-b)-(b+c)+(c-a+b)-(b-a-c)
=a+b-a+c+c-a+b-b+a+c
=(a-a+a)-(b-b+b)+(c+c+c)
=a-b+3c
\(a,A=\left(a+b-c\right)+\left(a-b\right)-\left(a-b-c\right)\)
\(=a+b-c+a-b-a+b+c\)
\(=a+b\)
\(b,B=\left(-a-b+c\right)+\left(a+b\right)\)
\(=-a-b+c+a+b\)
\(=c\)
\(c,C=-\left(a+b-c\right)+\left(-c\right)+\left(-a-b\right)-\left(a+b+c\right)\)
\(=-a-b+c-c-a-b-a-b-c\)
\(=-3a-3b-c\)
câu d cũng tương tự nha