\(3B=3^2.3^3.....3^{101}\)
\(3B-B=3^{101}-3\)
\(2B=3^{101}-3\)
\(B=\frac{3^{101}-3}{2}\)
Ta có: 3B=3B-B=3^2x3^3x3^4x3^5x...x3^101
2B=3B-B=(3^2x3^3x3^4x3^5x...x3^101)-(3x3^2x3^3x3^4x...x3^100)
=3^101-3
Suy ra B=3^101-3/2
B = 3 . 32 . 33 . 34 .... 3100
31B = 32 . 33 . 34 ..... 3100 . 3101
3B - B = 3101 - 31
2B = 3101 - 3
B = (3101 - 3) : 2