Question

Rút gọn biểu thức 

A=\(\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}\)

Answer 1

\(A=\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}\)

\(=\frac{a^3+a^2+a^2-1}{a^3+a^2+a^2+a+a+1}\)

\(=\frac{a^2\left(a+1\right)+\left(a+1\right)\left(a-1\right)}{a^2\left(a+1\right)+a\left(a+1\right)+\left(a+1\right)}\)

\(=\frac{\left(a^2+a-1\right)\left(a+1\right)}{\left(a^2+a+1\right)\left(a+1\right)}\)

\(=\frac{a^2+a-1}{a^2+a+1}\)

Answer 2

\(A=\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}=\frac{a^3+2a^2+\left(-1\right)}{a^3+2a^2+2a+1}=\frac{-1}{2a+1}\)

Answer 3

\(A=\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}\)

\(A=\frac{\left(a+1\right)\left(a^2+a-1\right)}{\left(a+1\right)\left(a^2+a+1\right)}=\frac{a^2+a-1}{a^2+a+1}\)

Answer 4

$A=\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}=\frac{a^3+2a^2+\left(-1\right)}{a^3+2a^2+2a+1}=\frac{-1}{2a+1}$

Answer 5

Rút gọn biểu thức 

A=$\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}$

Answer 6

$A=\frac{a^3+2a^2-1}{a^3+2a^2+2a+1}=\frac{a^3+2a^2+\left(-1\right)}{a^3+2a^2+2a+1}=\frac{-1}{2a+1}$

Answer 7

Bổ sung: ĐK là a khác -1 

Answer 8

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Answer 9

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