Lời giải:
$(2x+3)^2+(2x+5)^2=4x^2+12x+9+4x^2+20x+25$
$=8x^2+32x+34$
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Lời giải:
$(2x+3)^2+(2x+5)^2=4x^2+12x+9+4x^2+20x+25$
$=8x^2+32x+34$
rút gon cac bieu thuc (2x +3) mũ 2-(2x+5) mũ 2
rut gon bieu thuc.
A)(X^2-1).(X+2)-(X-2).(X^2+2X+4)
B)(2X+3)^2+(2X+5)^2-2.(2X+5).(2X+3)
rut gon bieu thuc :P=5x(x-3)(x+3)-(2x-3)^2+34x(x+2)-5(x+2)^3+25x-1
(4x-3)(3x+2)-(6x+1)(2x-5)+1
rut gon bieu thuc
Rut gon bieu thuc:
2(2x-3)^2+(x-2)(x+2)
(12x^2y^2-6x^3y^2):3x^2y:-4y(2x-5)
rut gon bieu thuc
(2x-1).(x-2)
Rut gon cacc bieu thuc sau : ( 4x - 3 ).( x - 5 ) - 2x ( 2x- 11)
giup mink nhe !!
rut gon bieu thuc sau
(2x-y+5)^2+(4x-2y+10)(y-2x)+(2x-y)^2
rut gon bieu thuc: 2x2(x-2) - 2x(x-1)(x+1)