Question

rut gon bieu thuc  (2x+1)^2-2(2x-1)(2x+1)+(2x-1)^2

giup mik vs

Answer 1

\(=\left[\left(2x+1\right)-\left(2x-1\right)\right]^2\\ =\left[2x+1-2x+1\right]^2\\ =\left(2\right)^2=4\)

Answer 2

\(\left(2x+1\right)^2-2\left(2x-1\right).\left(2x-1\right)+\left(2x-1\right)^2\)

\(=\left[\left(2x+1\right)-\left(2x-1\right)\right]^2\)

\(=\left[2x+1-2x+1\right]^2\)

\(=2^2\)

\(=4\)