Ta có : \(x^2+8x-20=\left(x-2\right)\left(x+10\right)\)
\(\left|x-2\right|=x-2\Leftrightarrow x\ge0\)
\(\left|x-2\right|=-\left(x-2\right)\Leftrightarrow x\le0\)
Vì \(x\ge0\)suy ra : \(\frac{x\left(x-2\right)}{\left(x-2\right)\left(x+10\right)}=\frac{x}{x+10}\)
Vì \(x\le0\)suy ra : \(\frac{x\left[-\left(x-2\right)\right]}{\left(x-2\right)\left(x+10\right)}=\frac{-x}{x+10}\)
Rút gọn A =\(\frac{x\left|x-2\right|}{x^2+8x-20}\)
Rút gọn A = \(\frac{x\left|x-2\right|}{x^2+8x-20}\)
Rút gọn \(A=\frac{x\left|x-2\right|}{x^2+8x-20}\)
Rút gọn biểu thức:
\(y=\frac{x\left|x-2\right|}{x^2+8x-20}\)
rút gọn \(A=\frac{x|x-2|}{x^2+8x-20}\)
Rút gọn: A=\(\frac{x. \text{Ix}-2I}{x^2+8x-20}\)
\(\left(1+\frac{1}{a+x}\right):\left(1-\frac{1}{a+x}\right).\left[1-\frac{1-\left(a^2+x^2\right)}{2ax}\right]\)
RÚT GỌN
rút gọn đa thức sau:
\(\left(8x^2+3-10\right)^{2008}.\left(8x^2+x-10\right)^{2009}\)
Rút gọn biểu thức \(\frac{x|x-2|}{x^2+8x-20}+12x-3\)
