\(\dfrac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\dfrac{2^{10}.3^9\left(3-1\right)}{2^9.3^{10}}=\dfrac{2^{10}.3^9.2}{2^9.3^{10}}=\dfrac{2^9.2.3^9.2}{2^9.3.3^9}=\dfrac{4}{3}\)
\(\dfrac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\dfrac{2^{10}.3^9\left(3-1\right)}{2^9.3^{10}}=\dfrac{2^{10}.3^9.2}{2^9.3^{10}}=\dfrac{2^{10}.2.3^9.2}{2^9.3.3^9}=\dfrac{4}{3}\)
Mình sửa ở phần phân số thứ 4 ạ ( \(2^{10}\Rightarrow2^9\), nãy mình viết nhầm ).
\(\dfrac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}\)
\(=\dfrac{2^{10}\cdot\left(3^{10}-3^9\right)}{2^9\cdot3^{10}}\)
\(=\dfrac{2^{10}\cdot3}{2^9\cdot3^{10}}\)
\(=\dfrac{2^9\cdot2\cdot3}{2^9\cdot3^{10}}\)
\(=\dfrac{2\cdot3}{3^{10}}\)
\(=\dfrac{6}{3^{10}}\)
\(\dfrac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}\)
\(=\dfrac{2^{10}\cdot3^9\cdot\left(3-1\right)}{2^9\cdot3^{10}}\)
\(=\dfrac{2^{10}\cdot3^9\cdot2}{2^9\cdot3^{10}}\)
\(=\dfrac{2^9\cdot2\cdot3^9\cdot2}{2^9\cdot3\cdot3^9}\)
\(=\dfrac{4}{3}\)
