a, \(\dfrac{1}{3}\) và \(\dfrac{5}{12}\)
Ta có: \(\dfrac{1}{3}=\dfrac{1\times4}{3\times4}=\dfrac{4}{12};\dfrac{5}{12}\) giữ nguyên
Vì \(4< 5\) nên \(\dfrac{4}{12}< \dfrac{5}{12}\)
b, \(\dfrac{5}{9}\) và \(\dfrac{8}{3}\)
Ta có: \(\dfrac{5}{9}< 1;\dfrac{8}{3}>1\)
Vậy \(\dfrac{5}{9}< \dfrac{8}{3}\)
c, \(\dfrac{6}{15}\) và \(\dfrac{2}{5}\)
Ta có: \(\dfrac{6}{15}=\dfrac{6\div3}{15\div3}=\dfrac{2}{5}\)
Vậy \(\dfrac{6}{15}=\dfrac{2}{5}\)