Question

QUY ĐỒNG CÁC PHÂN SỐ SAU :

\(\frac{12}{21}\)+\(\frac{11}{22}\)

\(\frac{9}{32}\)+ \(\frac{35}{11}\)

 

Answer 1

@nguyễn thị phương anh đây nhé :

\(\frac{12}{21}+\frac{11}{22}=\frac{264}{462}+\frac{231}{462}=\frac{495}{462}\)

\(\frac{9}{32}+\frac{35}{11}=\frac{99}{352}+\frac{1120}{352}=\frac{1219}{352}\)

Answer 2

\(\frac{12}{21}+\frac{11}{22}=\frac{4}{7}+\frac{1}{2}=\frac{8}{14}+\frac{7}{14}=\frac{15}{14}\)

\(\frac{9}{32}+\frac{35}{11}=\frac{99}{352}+\frac{1120}{352}=\frac{1219}{352}\)

Answer 3

\(\frac{12}{21}=\frac{12\text{x}22}{21\text{x}22}=\frac{264}{462}\); \(\frac{11}{22}=\frac{11\text{x}21}{22\text{x}21}=\frac{231}{462}\);

Vậy: \(\frac{12}{21}+\frac{11}{22}=\frac{264}{462}+\frac{231}{462}=\frac{264+231}{462}=\frac{495}{462}\)

\(\frac{9}{32}=\frac{9\text{x}11}{32\text{x}11}=\frac{99}{352}\);\(\frac{35}{11}=\frac{35\text{x}32}{11\text{x}32}=\frac{1120}{352}\)

Vậy: \(\frac{9}{32}+\frac{35}{11}=\frac{99}{352}+\frac{1120}{352}=\frac{99+1120}{352}=\frac{1219}{352}\)