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Điền số đo thích hợp vào chỗ chấm :6km^223456m^{^2}.....km^2.....hm^2.....dam^2.....m^2.....km^25km^2246dam^2.....km^2.....hm^2.....dam^2.....km^257932cm^2.....m^2.....dm^2.....cm^2.....m^25,405m^2.....m^2.....dm^2.....cm^2.....cm^2.....dm^237805cm^2.....m^2.....dm^2.....cm^2.....m^257950cm^2.....m^2.....dm^2.....cm^2.....dm^2
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Điền số đo thích hợp vào chỗ chấm :
6km\(^2\)23456m\(^{^2}\)=.....km\(^2\).....hm\(^2\).....dam\(^2\).....m\(^2\)=.....km\(^2\)
5km\(^2\)246dam\(^2\)=.....km\(^2\).....hm\(^2\).....dam\(^2\)=.....km\(^2\)
57932cm\(^2\)=.....m\(^2\).....dm\(^2\).....cm\(^2\)=.....m\(^2\)
5,405m\(^2\)=.....m\(^2\).....dm\(^2\).....cm\(^2\)=.....cm\(^2\)=.....dm\(^2\)
37805cm\(^2\)=.....m\(^2\).....dm\(^2\).....cm\(^2\)=.....m\(^2\)
57950cm\(^2\)=.....m\(^2\).....dm\(^2\).....cm\(^2\)=.....dm\(^2\)
8,96:x-0,52,030,54-1,2cdotx0,06Chuyển các phân số sau thành hỗn sốfrac{17}{5};frac{139}{12};frac{150}{13}
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\(8,96\)\(:\)\(x\)\(-\)\(0,5\)\(=\)\(2,03\)
\(0,54\)\(-\)\(1,2\)\(\cdot\)\(x\)\(=\)\(0,06\)
Chuyển các phân số sau thành hỗn số
\(\frac{17}{5}\)\(;\)\(\frac{139}{12}\)\(;\)\(\frac{150}{13}\)
55+88-77+6666-4444??Trảlờinhanhmktkchonha~KimSởSở~
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\(55+88-77+6666-4444=?\)\(?\)
\(Trả\)\(lời\)\(nhanh\)\(mk\)\(tk\)\(cho\)\(nha\)
\(~\)\(Kim\)\(Sở\)\(Sở\)\(~\)
\(\frac{1212}{3434}\)\(+\)\(x\)\(-\)\(\frac{13}{102}\)\(=\)\(1\)\(-\)\(\frac{107}{102}\)
frac{2}{3}+frac{5}{8}+frac{9}{3}:frac{4}{7}(frac{2}{6}+frac{1}{1}) ..............AinhanhaiđúngMkTick
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\(\frac{2}{3}\)\(+\frac{5}{8}\)\(+\frac{9}{3}\)\(:\frac{4}{7}\)(\(\frac{2}{6}\)\(+\frac{1}{1}\)) \(=\)..............
\(Ai\)\(nhanh\)\(ai\)\(đúng\)\(Mk\)\(Tick\)
2m^213dm^2...................m^21m^220dm^2..........m^24m^25dm^2.............m^23m^217dm^2............dm^2
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\(2m^2\)\(13dm^2\)\(=...................m^2\)
\(1m^2\)\(20dm^2\)\(=..........m^2\)
\(4m^2\)\(5dm^2\)\(=.............m^2\)
\(3m^2\)\(17dm^2\)\(=............dm^2\)
1.frac{1}{2}+frac{2}{3}+frac{3}{4}frac{4}{5}+frac{4}{3}+frac{6}{7}frac{1}{4}+frac{2}{5}+frac{1}{3}frac{3}{5}+frac{5}{6}+frac{7}{9}frac{8}{9}-frac{5}{6}frac{99}{108}-frac{40}{72}frac{16}{17}-frac{12}{13}frac{99}{153}-frac{75}{125}
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1.
\(\frac{1}{2}\)+\(\frac{2}{3}\)+\(\frac{3}{4}\)
\(\frac{4}{5}\)+\(\frac{4}{3}\)+\(\frac{6}{7}\)
\(\frac{1}{4}\)+\(\frac{2}{5}\)+\(\frac{1}{3}\)
\(\frac{3}{5}\)+\(\frac{5}{6}\)+\(\frac{7}{9}\)
\(\frac{8}{9}\)-\(\frac{5}{6}\)
\(\frac{99}{108}\)-\(\frac{40}{72}\)
\(\frac{16}{17}\)-\(\frac{12}{13}\)
\(\frac{99}{153}\)-\(\frac{75}{125}\)
Tìm x :
\(320\): \(x\)\(-\)\(10\)\(=\)\(5\)\(x\)\(48\): \(24\)
\(\frac{1}{2}\)\(+\)\(\frac{1}{4}\)\(+\)\(\frac{1}{8}\)\(+\)\(\frac{1}{16}\)...\(+\)\(\frac{1}{2048}\)
\(x\)\(:\)\(0,1\)\(+\)\(x\)\(\cdot5\)\(=24\)