Bài toán 1.2 :
\(3a\left(b^2-2c\right)-\left(a-4\right)\left(2c-b^2\right)\)
\(=3a\left(b^2-2c\right)+\left(a-4\right)\left(b^2-2c\right)\)
\(=\left(b^2-2c\right)\left(3a+a-4\right)\)
\(=\left(b^2-2c\right)\left(4a-4\right)\)
con hai bai nua ban giai ho minh luon di