\(6x^2-7x-20\)
\(=6x^2-15x+8x-20\)
\(=3x\left(2x-5\right)+4\left(2x-5\right)\)
\(=\left(2x-5\right)\left(3x+4\right)\)
6x2-7x-20
=6x2-15x+8x-20
=6x2+8x-15x-20
=3x(2x-5)-4(2x-5)
=(2x-5)(3x-4)
Ta có: \(6x^2-15x+8x-20\)
\(3x\left(2x-5\right)+4\left(2x-5\right)\)
\(\Rightarrow\left(2x-5\right)\left(3x+4\right)\)
Nếu thấy đúng thì chọn giùm mình nhé,mình xin cảm ơn