Question

PT đa thức sau thành nhân tử     x^3+27  +(x+3)(x-9)

Answer 1

x^3+27+(x+3)(x-9)=(x+3)(x²+3x+9)+(x+3)(x+9)

=(x+3)(x²+3x+9+x+9)

=(x+3)(x²+4x+18)

Answer 2

x^3+27+(x+3)(x-9)=(x+3)(x²+3x+9)+(x+3)(x-9)

=(x+3)(x²+3x+9+x-9)

=(x+3)(x²+4x)

=x(x+3)(x+4)