Question

Phương pháp 2: dùng hằng đẳng thức

1) \(4x^2-y^2\)

2) \(8x^3-27\)

3) \(x^3+27y^3\)

4) \(x^2-25y^2\)

5) \(8x^3+\frac{1}{27}\)

Answer 1

1)  \(4x^2-y^2=\left(2x-y\right)\left(2x+y\right)\)

2) \(8x^3-27=\left(2x-3\right)\left(4x^2+6x+9\right)\)

3) \(x^3+27y^3=\left(x+3y\right)\left(x^2-3xy+9y^2\right)\)

4) \(x^2-25y^2=\left(x-5y\right)\left(x+5y\right)\)

5) \(8x^3+\frac{1}{27}=\left(2x+\frac{1}{3}\right)\left(4x^2-\frac{2}{3}x+\frac{1}{9}\right)\)